Question

the accompanying bar graph shows the resident population and the land area of a particular country for selected years from 1800 through 2019. use the information to complete parts (a) and (b) below. a. find the population density of the country, to the nearest tenth, in 1900 and in 2019. b. find the percent increase in population density, to the nearest tenth of a percent, from 1900 to 2019. click here to view a bar graph showing resident population and the land area of a particular country for selected years from 1800 through 2019. a. the population density, to the nearest tenth, in 1900 was (round to the nearest tenth as needed.)

Explanation:

To solve this problem, we need the data from the bar graph (resident population and land area for the year 1900). Since the bar graph is not visible here, I'll assume typical values (for example, if in 1900 the population was \( 76,212,168 \) and the land area was \( 3,540,845 \) square miles, which are approximate values for the USA in 1900):

Part (a): Population Density in 1900

Population density is calculated as \( \text{Population Density} = \frac{\text{Population}}{\text{Land Area}} \).

Step 1: Identify Population and Land Area (from bar graph)

Let’s assume (from typical data):

• Population in 1900: \( P = 76,212,168 \) people
• Land Area in 1900: \( A = 3,540,845 \) square miles

Step 2: Calculate Population Density

\[
\text{Population Density} = \frac{76,212,168}{3,540,845} \approx 21.5 \text{ people per square mile}
\]

Final Answer (for Part a, assuming the above data):

The population density in 1900, to the nearest tenth, was \( \boldsymbol{21.5} \) people per square mile.

(Note: If the bar graph has different values, substitute \( P \) and \( A \) with the actual numbers from the graph and recalculate.)

Answer:

To solve this problem, we need the data from the bar graph (resident population and land area for the year 1900). Since the bar graph is not visible here, I'll assume typical values (for example, if in 1900 the population was \( 76,212,168 \) and the land area was \( 3,540,845 \) square miles, which are approximate values for the USA in 1900):

Part (a): Population Density in 1900

Population density is calculated as \( \text{Population Density} = \frac{\text{Population}}{\text{Land Area}} \).

Step 1: Identify Population and Land Area (from bar graph)

Let’s assume (from typical data):

• Population in 1900: \( P = 76,212,168 \) people
• Land Area in 1900: \( A = 3,540,845 \) square miles

Step 2: Calculate Population Density

\[
\text{Population Density} = \frac{76,212,168}{3,540,845} \approx 21.5 \text{ people per square mile}
\]

Final Answer (for Part a, assuming the above data):

The population density in 1900, to the nearest tenth, was \( \boldsymbol{21.5} \) people per square mile.

(Note: If the bar graph has different values, substitute \( P \) and \( A \) with the actual numbers from the graph and recalculate.)