Question

1. according to the american veterinary medical association, 31.6% of american households own a dog. what is the probability that a randomly selected household does not own a dog?

Explanation:

Step1: Recall probability rule

The sum of the probability of an event occurring and the probability of it not occurring is 1. Let $P(A)$ be the probability of a household owning a dog and $P(\overline{A})$ be the probability of a household not owning a dog. So $P(A)+P(\overline{A}) = 1$.

Step2: Substitute given value

We know that $P(A)=0.316$. Then $P(\overline{A})=1 - P(A)$. Substituting the value of $P(A)$ into the formula, we get $P(\overline{A})=1 - 0.316$.

Step3: Calculate result

$P(\overline{A})=0.684$.

Answer:

$0.684$