Question

action and reaction on different masses
-80 n
the person experiences a
reaction force of -80 n.
what is the acceleration
of the person?
remember: f = ma
40 kg
+2.0 m/s²
+0.38 m/s²
-2.0 m/s²
-0.38 m/s²

Explanation:

Step1: Recall the formula \( F = ma \)

We know that \( F = ma \), where \( F \) is force, \( m \) is mass, and \( a \) is acceleration. We need to solve for \( a \), so we can rearrange the formula to \( a=\frac{F}{m} \).

Step2: Identify the values of \( F \) and \( m \)

The force \( F \) acting on the person is \(-80\space N\) and the mass \( m \) of the person is \( 40\space kg \).

Step3: Calculate the acceleration

Substitute the values of \( F \) and \( m \) into the formula \( a=\frac{F}{m} \). So \( a = \frac{-80\space N}{40\space kg} \). Calculating this, we get \( a=-2.0\space m/s^{2} \).

Answer:

\(-2.0\space m/s^{2}\)