Question

x is an acute angle. find the value of x in degrees. \\(\cos(x) = \frac{\sqrt{2}}{2}\\) \\(x = \square^\circ\\) submit

Explanation:

Step1: Recall cosine of special angles

We know that for acute angles, $\cos(45^\circ) = \frac{\sqrt{2}}{2}$.

Step2: Match given value to angle

Since $\cos(x) = \frac{\sqrt{2}}{2}$ and $x$ is acute, $x$ equals the angle whose cosine is $\frac{\sqrt{2}}{2}$.

Answer:

$45$