Question

adam takes a bus on a school field - trip. the bus route is split into the five legs listed in the table. find the average velocity for each leg of the trip. then arrange the legs of the trip from highest velocity to lowest.

leg	distance (km)	time (min)
b	25	15
c	24	8
d	48	12
e	15	7

Explanation:

Step1: Calculate velocity for each leg

Velocity = Distance/Time.
Leg A: $18/9 = 2$ km/min; Leg B: $25/15 ≈ 1.67$ km/min; Leg C: $24/8 = 3$ km/min; Leg D: $48/12 = 4$ km/min; Leg E: $15/7 ≈ 2.14$ km/min.

Step2: Order velocities from highest to lowest

4 (D) > 3 (C) > 2.14 (E) > 2 (A) > 1.67 (B).

Answer:

D, C, E, A, B