Question

after a golfer hits a golf ball, the ball leaves the ground with an initial vertical velocity of 100 feet per second.
$h = -16t^2 + 100t$
for how many seconds is the golf ball in the air before landing on the ground?
use desmos to help.
10.62 seconds
6.25 seconds
8.75 seconds
3.25 seconds

Explanation:

Step1: Set height to zero

When the ball lands, \( h = 0 \). So we solve \( 0=-16t^{2}+100t \).

Step2: Factor the equation

Factor out \( 4t \): \( 0 = 4t(-4t + 25) \).

Step3: Solve for t

Set each factor to zero: \( 4t = 0 \) gives \( t = 0 \) (initial time), and \( -4t + 25 = 0 \) gives \( -4t=-25 \), so \( t=\frac{25}{4}=6.25 \).

Answer:

6.25 seconds (corresponding to the option: 6.25 seconds)