Question

agricultural mechanics test – reading a rule
student name
instructions: after each letter write the correct measurement indicated by the arrow. reduce to the lowest terms.
ruler image with labels a - l
a. ____ b. __ c. __ d. ____
e. ____ f. __ g. __ h. ____
i. ____ j. __ k. __ l. ____
instructions: from the following information, solve the following problems. reduce to the lowest terms.

1. what is the sum of the lengths of measurements “c”, “h”, “k” and “l”?
2. how much larger is measurement “f” than measurement “e”?

Explanation:

Step1: Read ruler measurements

The ruler has 16 divisions per inch, so each small mark = $\frac{1}{16}$ inch.

• A: $0$ inches
• B: $\frac{2}{16} = \frac{1}{8}$ inches
• C: $\frac{4}{16} = \frac{1}{4}$ inches
• D: $\frac{6}{16} = \frac{3}{8}$ inches
• E: $\frac{7}{16}$ inches
• F: $1 + \frac{4}{16} = 1 + \frac{1}{4} = \frac{5}{4}$ inches
• G: $2$ inches
• H: $2 + \frac{4}{16} = 2 + \frac{1}{4} = \frac{9}{4}$ inches
• I: $2 + \frac{8}{16} = 2 + \frac{1}{2} = \frac{5}{2}$ inches
• J: $3 + \frac{2}{16} = 3 + \frac{1}{8} = \frac{25}{8}$ inches
• K: $3 + \frac{8}{16} = 3 + \frac{1}{2} = \frac{7}{2}$ inches
• L: $4 + \frac{1}{16} = \frac{65}{16}$ inches

Step2: Solve sum for Q1

Sum C, H, K, L:
$\frac{1}{4} + \frac{9}{4} + \frac{7}{2} + \frac{65}{16}$
Convert to 16 denominator:
$\frac{4}{16} + \frac{36}{16} + \frac{56}{16} + \frac{65}{16} = \frac{4+36+56+65}{16} = \frac{161}{16} = 10\frac{1}{16}$

Step3: Solve difference for Q2

Subtract E from F:
$\frac{5}{4} - \frac{7}{16} = \frac{20}{16} - \frac{7}{16} = \frac{13}{16}$

Answer:

Ruler Measurements:

A. $0$ inches
B. $\frac{1}{8}$ inches
C. $\frac{1}{4}$ inches
D. $\frac{3}{8}$ inches
E. $\frac{7}{16}$ inches
F. $1\frac{1}{4}$ inches
G. $2$ inches
H. $2\frac{1}{4}$ inches
I. $2\frac{1}{2}$ inches
J. $3\frac{1}{8}$ inches
K. $3\frac{1}{2}$ inches
L. $4\frac{1}{16}$ inches

Problem 1:

$10\frac{1}{16}$ inches

Problem 2:

$\frac{13}{16}$ inches