Question

2 al is using the standard multiplication algorithm, but he hasnt filled in all the numbers. help him complete each problem by filling in the gray boxes correctly.
(three multiplication problems with gray boxes to fill, the first one:
2
3 4
× 2 6
2 0 square
+ 6 square 0
square 8 4
the second one:
7
1 9
× 1 8
square square 2
+ 1 9 square
3 square 2
the third one:
^1_4
5 6
× 2 7
3 9 square
+ 1 square 2 0
1 5 1 square
)

Explanation:

Step1: Solve first multiplication

First, identify the top number is 34, multiplier 26.

• Multiply 34 by 6: $34 \times 6 = 204$ → missing box is 4.
• Multiply 34 by 20: $34 \times 20 = 680$ → missing box is 8.
• Sum: $204 + 680 = 884$ → missing box is 8.

Step2: Solve second multiplication

Top number is 19, multiplier 18.

• Multiply 19 by 8: $19 \times 8 = 152$ → missing boxes are 1, 5.
• Multiply 19 by 10: $19 \times 10 = 190$ → missing box is 0.
• Sum: $152 + 190 = 342$ → missing box is 4.

Step3: Solve third multiplication

Top number is 56, multiplier 27.

• Multiply 56 by 7: $56 \times 7 = 392$ → missing box is 2.
• Multiply 56 by 20: $56 \times 20 = 1120$ → missing box is 1.
• Sum: $392 + 1120 = 1512$ → missing box is 2.

Answer:

1. First problem gray boxes (top to bottom): 4, 8, 8
2. Second problem gray boxes (top to bottom): 1, 5, 0, 4
3. Third problem gray boxes (top to bottom): 2, 1, 2

Filled full problems:
1.

    34
  ×26
  ----
   204
 +680
 ----
   884

2.

    19
  ×18
  ----
   152
 +190
 ----
   342

3.

    56
  ×27
  ----
   392
+1120
 ----
  1512