Question

algebra and geometry review factoring a difference of squares in one variable: advanced factor. 81 - 64y^2

Explanation:

Step1: Identify perfect - squares

We know that $81 = 9^2$ and $64y^{2}=(8y)^{2}$.

Step2: Apply difference - of - squares formula

The difference - of - squares formula is $a^{2}-b^{2}=(a + b)(a - b)$. Here $a = 9$ and $b = 8y$. So $81-64y^{2}=(9 + 8y)(9 - 8y)$.

Answer:

$(9 + 8y)(9 - 8y)$