Question

always use significant figure rules. remember that these rules apply to all numbers that are measurements. a train goes up a hill with a 15° incline. if the train has constant speed of 22 m/s, what are the vertical and horizontal components of the trains velocity? (remember to use the law of sine and cosines for this problem)
y = m/s
x = 20 m/s
21
5.7

Explanation:

Step1: Encontrar la componente vertical

Utilizamos la fórmula $v_y = v\sin\theta$, donde $v = 22$ m/s y $\theta=15^{\circ}$.
$v_y = 22\times\sin(15^{\circ})$
$v_y = 22\times0.2588 = 5.6936\approx5.7$ m/s

Step2: Encontrar la componente horizontal

Utilizamos la fórmula $v_x = v\cos\theta$, donde $v = 22$ m/s y $\theta = 15^{\circ}$.
$v_x=22\times\cos(15^{\circ})$
$v_x = 22\times0.9659 = 21.2498\approx21$ m/s

Answer:

$y = 5.7$ m/s
$x = 21$ m/s