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angle bisector and inverse hw jh bisects ∠vjs. if ∠hjs = 5x + 10 and ∠v…

Question

angle bisector and inverse hw
jh bisects ∠vjs.
if ∠hjs = 5x + 10 and ∠vjh = -4 + 7x
x =

Explanation:

Step1: Recall angle - bisector property

Since $\overline{JH}$ bisects $\angle VJS$, then $\angle HJS=\angle VJH$.

Step2: Set up the equation

Set $5x + 10=-4 + 7x$.

Step3: Solve for $x$

Subtract $5x$ from both sides: $10=-4 + 7x-5x$.
Simplify to get $10=-4 + 2x$.
Add 4 to both sides: $10 + 4=2x$, so $14 = 2x$.
Divide both sides by 2: $x=\frac{14}{2}=7$.

Answer:

$7$