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Question
6.2 - angle bisectors - spiral review
find each measure.
- $m\angle abf$
- $m\angle yba$
- $mk$
- $m\angle ewl$
- $iu$
- $m\angle myw$
(the corresponding geometric figures with angle markings and algebraic expressions: $43^\circ$, $47^\circ$, $2x + 1$, $3x - 3$, $(7x + 5)^\circ$, $(3x + 21)^\circ$, $19^\circ$, $2x + 5$, $7x$, $(4x - 1)^\circ$, $(2x + 5)^\circ$ are present in the figures)
Step1: Solve for $\boldsymbol{m\angle ABF}$
$AC \parallel EF$, $BF$ bisects $\angle ABC$.
$\angle ABC = 43^\circ$, so $\angle ABF = \frac{1}{2}\angle ABC$
$\angle ABF = \frac{1}{2} \times 43^\circ = 21.5^\circ$
Step2: Solve for $\boldsymbol{m\angle YBA}$
$YB \parallel AF$, $\angle ADF = 47^\circ$, so $\angle YAB = \angle ADF = 47^\circ$.
$\angle YBA = 90^\circ - \angle YAB$
$\angle YBA = 90^\circ - 47^\circ = 43^\circ$
Step3: Solve for $\boldsymbol{x}$ (Question 3)
$KM$ and $KT$ are angle bisectors, so $2x+1=3x-8$
$3x-2x=1+8$
$x=9$
Step4: Solve for $\boldsymbol{m\angle EWL}$
$WL$ is an angle bisector, so $7x+5=3x+21$
$7x-3x=21-5$
$4x=16 \implies x=4$
$m\angle EWL = 7x+5 = 7(4)+5=33^\circ$
Step5: Solve for $\boldsymbol{IU}$
$RU$ is an angle bisector, so $2x+5=7x$
$7x-2x=5$
$5x=5 \implies x=1$
$IU=7x=7(1)=7$
Step6: Solve for $\boldsymbol{m\angle MYW}$
$YM$ is an angle bisector, so $4x-1=2x+5$
$4x-2x=5+1$
$2x=6 \implies x=3$
$m\angle MYW = 2x+5 = 2(3)+5=11^\circ$
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- $21.5^\circ$
- $43^\circ$
- $9$
- $33^\circ$
- $7$
- $11^\circ$