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Question
angle kjl measures (7x - 8)°. angle kml measures (3x + 8)°. what is the measure of arc kl? 20° 48° 96° 40°
Step1: Recall inscribed - angle theorem
In a circle, inscribed angles that intercept the same arc are equal. So, $\angle KJL=\angle KML$.
$$7x - 8=3x + 8$$
Step2: Solve the equation for $x$
Subtract $3x$ from both sides: $7x-3x - 8=3x-3x + 8$, which simplifies to $4x-8 = 8$. Then add 8 to both sides: $4x-8 + 8=8 + 8$, so $4x=16$. Divide both sides by 4: $x = 4$.
Step3: Find the measure of $\angle KML$
Substitute $x = 4$ into the expression for $\angle KML$: $\angle KML=3x + 8=3\times4+8=12 + 8=20^{\circ}$.
Step4: Find the measure of arc $KL$
The measure of an arc is twice the measure of the inscribed - angle that intercepts it. So the measure of arc $KL = 2\angle KML$.
$$\text{Measure of arc }KL=2\times20^{\circ}=40^{\circ}$$
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$40^{\circ}$