Question

an angle in standard position measures $\frac{pi}{2}$ radians, and $p(0, 1)$ is on the terminal side of the angle. what is the value of the cosine of this angle?
-1
0
1
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Explanation:

Step1: Recall cosine - angle relationship

The cosine of an angle $\theta$ in standard position with a point $(x,y)$ on its terminal - side is given by $\cos\theta=\frac{x}{r}$, where $r = \sqrt{x^{2}+y^{2}}$.

Step2: Identify $x$, $y$ values

Given the point $P(0,1)$, we have $x = 0$ and $y = 1$.

Step3: Calculate $r$

$r=\sqrt{0^{2}+1^{2}}=\sqrt{0 + 1}=1$.

Step4: Calculate cosine value

$\cos\theta=\frac{x}{r}=\frac{0}{1}=0$.

Answer:

B. 0