Question

answer each of the following your notes as an example if needed. 1. what’s the empirical formula of a molecule containing 39.3% carbon, 8.3% hydrogen, and 54.4% oxygen? symbol percentage percent as mass divide by small round or multiply subscripts c 39.3 \\(\frac{39.3}{12.01}=3.27\\) h 8.3 \\(\frac{8.3}{1.01}=8.21\\) o 54.4 \\(\frac{54.4}{16.00}=3.4\\) answer =

Explanation:

Step1: Identify smallest mole value

Smallest value: $3.27$

Step2: Divide all moles by small

C: $\frac{3.27}{3.27}=1$
H: $\frac{8.21}{3.27}\approx2.51$
O: $\frac{3.4}{3.27}\approx1.04$

Step3: Multiply to get whole numbers

Multiply all by 2:
C: $1\times2=2$
H: $2.51\times2\approx5$
O: $1.04\times2\approx2$

Answer:

$\text{C}_2\text{H}_5\text{O}_2$