Question

answer the following questions. remember to think about classifying matter and state
1 what are all the differences between cuso₄ and cuso₄ (aq)?
2 why was air classified as a homogeneous mixture and not a compound?

1. what is the easiest way to determine if something is an element?

4 if you were to look at the atoms in the copper wire, what would you observe?

Explanation:

1. $CuSO_4$ vs $CuSO_4(aq)$: $CuSO_4$ is the solid copper - sulfate compound. $CuSO_4(aq)$ represents an aqueous solution of copper - sulfate, where the $CuSO_4$ has dissolved in water. In the solid form, the ions are in a fixed lattice structure. In the aqueous solution, the $Cu^{2 + }$ and $SO_4^{2 - }$ ions are surrounded by water molecules (hydrated) and are free to move.
2. Air as a homogeneous mixture: Air is composed of nitrogen, oxygen, carbon - dioxide, argon, and other trace gases. These components are not chemically bonded to each other. The proportions of these gases can vary slightly in different locations. In a compound, the elements are chemically combined in a fixed ratio.
3. Determining an element: Check if it cannot be broken down into simpler substances by chemical means. Elements are pure substances made up of only one type of atom.
4. Atoms in copper wire: Copper wire is made of copper atoms. You would observe a lattice of copper atoms held together by metallic bonds. The atoms are arranged in a regular, repeating pattern, and there are delocalized electrons that can move freely throughout the lattice, which is responsible for the electrical and thermal conductivity of copper.

Answer:

1. $CuSO_4$ is solid with fixed ion - lattice; $CuSO_4(aq)$ is an aqueous solution with hydrated, mobile ions.
2. Air components are not chemically bonded and proportions can vary; compounds have fixed - ratio chemical bonds.
3. Check if it can't be broken down by chemical means.
4. A lattice of copper atoms held by metallic bonds with delocalized electrons.