Question

apply the distributive property to show 3i(2i)+(-3i - 5) in its simplest form (1 point)

Explanation:

Step1: Apply distributive property

$3i[(2i)+(- 3i - 5)]=3i\times2i+3i\times(-3i - 5)$

Step2: Multiply terms

$3i\times2i = 6i^{2}$ and $3i\times(-3i - 5)=-9i^{2}-15i$

Step3: Recall $i^{2}=-1$

$6i^{2}=-6$ and $-9i^{2}=9$

Step4: Combine like - terms

$-6 + 9-15i=3-15i$

Answer:

$3 - 15i$