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applying trigonometric ratios to estimate side lengths rounded to the n…

Question

applying trigonometric ratios to estimate side lengths
rounded to the nearest tenth, what is the length of ln?
\\(\sin(20^{\circ}) = \frac{ln}{8}\\)
\\((8)\sin(20^{\circ}) = ln\\)
\\(\square = ln\\)

Explanation:

Step1: Recall the value of sin(20°)

We know that $\sin(20^\circ) \approx 0.3420$.

Step2: Calculate 8 times sin(20°)

Multiply 8 by the approximate value of $\sin(20^\circ)$: $8\times0.3420 = 2.736$.

Step3: Round to the nearest tenth

Rounding 2.736 to the nearest tenth gives 2.7.

Answer:

2.7