Question

1. the area of a rectangle is 36 square centimeters, and its length is 9 centimeters. what is the width of the rectangle? a. elsa wants to draw a second rectangle that is the same length but 3 times as wide. draw and label elsas second rectangle. b. what is the perimeter of elsas second rectangle? c.

Explanation:

Step1: Find width of first rectangle

Use formula $A = lw$ (where $A$ is area, $l$ is length, $w$ is width). Given $A = 36$ square - cm and $l = 9$ cm. Then $w=\frac{A}{l}=\frac{36}{9}=4$ cm.

Step2: Determine dimensions of second rectangle

Width of second rectangle is the same as first, $w_2 = 4$ cm. Length of second rectangle is 3 times the width, so $l_2=3\times4 = 12$ cm.

Step3: Calculate perimeter of second rectangle

Use formula $P = 2(l + w)$. Substitute $l = 12$ cm and $w = 4$ cm. Then $P=2(12 + 4)=2\times16 = 32$ cm.

Answer:

32 cm