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Question
(a) the area of a rectangular parking lot is 4628 m². if the width of the parking lot is 52 m, what is its length? length of the parking lot: m (b) the perimeter of a rectangular pool is 268 m. if the length of the pool is 75 m, what is its width? width of the pool: m
Step1: Recall rectangle area formula
The area of a rectangle is $A = l \times w$, where $A$ is area, $l$ is length, $w$ is width. Rearrange to solve for $l$: $l = \frac{A}{w}$
Step2: Substitute values for (a)
Substitute $A = 4628\ \text{m}^2$, $w = 52\ \text{m}$:
$l = \frac{4628}{52} = 89$
Step3: Recall rectangle perimeter formula
The perimeter of a rectangle is $P = 2(l + w)$, where $P$ is perimeter, $l$ is length, $w$ is width. Rearrange to solve for $w$: $w = \frac{P}{2} - l$
Step4: Substitute values for (b)
Substitute $P = 268\ \text{m}$, $l = 75\ \text{m}$:
$w = \frac{268}{2} - 75 = 134 - 75 = 59$
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Length of the parking lot: $89$ m
Width of the pool: $59$ m