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assignment factor the common factor out of each expression. 1) $-25x^3 …

Question

assignment
factor the common factor out of each expression.

  1. $-25x^3 - 20x^4$
  2. $12x^8 + 9x^4$
  3. $35x^5u - 28x^4u^2 + 14x^4$
  4. $-50y^3x^2 + 20y^4x + 30y^4$
  5. $8mn^4 + 20m^2n^2 + 16mn - 16m$
  6. $60x^2y + 30xy^2 + 12x^2y + 18xy$

Explanation:

Response
Problem 1: \(-25x^{3}-20x^{4}\)

Step 1: Identify the GCF of coefficients and variables

The GCF of \(-25\) and \(-20\) is \(5\) (we take the negative sign for the common factor to make the leading term positive, so \(-5\)). For the variables, the GCF of \(x^{3}\) and \(x^{4}\) is \(x^{3}\). So the common factor is \(-5x^{3}\).

Step 2: Factor out the common factor

\(-25x^{3}-20x^{4}=-5x^{3}(5 + 4x)\)

Step 1: Find the GCF of coefficients and variables

GCF of \(12\) and \(9\) is \(3\). GCF of \(x^{8}\) and \(x^{4}\) is \(x^{4}\). So common factor is \(3x^{4}\).

Step 2: Factor out the common factor

\(12x^{8}+9x^{4}=3x^{4}(4x^{4}+3)\)

Step 1: Determine the GCF

GCF of \(35\), \(-28\), and \(14\) is \(7\). GCF of \(x^{5}u\), \(x^{4}u^{2}\), and \(x^{4}\) is \(x^{4}\). So common factor is \(7x^{4}\).

Step 2: Factor out the common factor

\(35x^{5}u - 28x^{4}u^{2}+14x^{4}=7x^{4}(5xu - 4u^{2}+2)\)

Answer:

\(-5x^{3}(5 + 4x)\)

Problem 2: \(12x^{8}+9x^{4}\)