Question

assuming 50% efficiency, 150 kcals of chemical energy would result in __________ of kinetic energy. a. 50 kcals b. 75 kcals c. 100 kcals d. 150 kcals please select the best answer from the choices provided.

Explanation:

Step1: Recall efficiency formula

Efficiency = $\frac{\text{Output energy}}{\text{Input energy}}\times100\%$. We know efficiency = 50% and input energy (chemical energy) = 150 kcals. Let output energy (kinetic energy) be $E$.

Step2: Rearrange formula to find output energy

$50\%=\frac{E}{150}\times100\%$, so $E=\frac{50}{100}\times150$.

Step3: Calculate the value

$E = 75$ kcals.

Answer:

B. 75 kcals