Question

atoms, ions and molecules
naming binary ionic compounds
fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table:
some ionic compounds
cation\tanion\tempirical formula\tname of compound
k⁺\tbr⁻\tkbr\tpotassium bromide
k⁺\tf⁻\tkf\tpotassium fluoride
k⁺\tcl⁻\tkcl\tpotassium chloride
k⁺\ti⁻\tki\tpotassium iodide

Explanation:

The table shows the formation of binary ionic compounds from potassium ions ($K^+$) and various halide ions. The pattern is that the empirical formula is formed by combining the cation ($K^+$) and anion in a 1:1 ratio (since $K^+$ has a +1 charge and each halide ion has a -1 charge), and the name is "potassium" followed by the name of the halide (changing the suffix of the halogen to -ide, e.g., bromine → bromide, chlorine → chloride, etc.).

For example, with $K^+$ and $Br^-$, the formula is $KBr$ (potassium bromide); with $K^+$ and $F^-$, it's $KF$ (potassium fluoride); with $K^+$ and $Cl^-$, it's $KCl$ (potassium chloride); and with $K^+$ and $I^-$, it's $KI$ (potassium iodide). This follows the rules of naming binary ionic compounds: name the cation first (using its elemental name) and then the anion with the -ide suffix, and the formula is determined by the charge balance (here, +1 and -1 charges balance in a 1:1 ratio).

If we were to fill in more, say for a new halide like $K^+$ and $At^-$ (astatide), the formula would be $KAt$ and the name potassium astatide, following the same pattern.

Answer:

The table follows the pattern of binary ionic compound formation: cation ($K^+$) + anion (halide, -1 charge) → empirical formula (1:1 ratio) and name "potassium [halide -ide]". For example, $K^+$ and $Br^-$ form $KBr$ (potassium bromide), $K^+$ and $F^-$ form $KF$ (potassium fluoride), etc.