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Question
au3l3.05_special angle pairs quiz started: oct 6 at 8:07pm quiz instructions aul3.05_special angle pairs quiz.mp4 question 1 1 pts find the value of x. (x + 16)° (4x - 5)°
Step1: Identify angle - pair relationship
The two angles $(x + 16)^{\circ}$ and $(4x-5)^{\circ}$ are vertical angles. Vertical angles are equal.
So, $x + 16=4x - 5$.
Step2: Solve the equation for x
Subtract x from both sides: $16=4x - x-5$.
Simplify to get $16 = 3x-5$.
Add 5 to both sides: $16 + 5=3x$, so $21 = 3x$.
Divide both sides by 3: $x=\frac{21}{3}=7$.
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$7$