Question

the average diameter of an atom’s nucleus is about 1×10^(-14) meter. the diameter of a proton is about 1×10^(-15) meter. the diameter of a proton times 10 raised to what power is equivalent to the diameter of a nucleus? 10^(-15)×10^? = 10^(-14)

Explanation:

Step1: Use exponent - rule

According to the rule \(a^m\times a^n=a^{m + n}\), let the unknown power be \(x\). So \(10^{-15}\times10^{x}=10^{-14}\). Then \(-15 + x=-14\).

Step2: Solve for \(x\)

Add 15 to both sides of the equation \(-15 + x=-14\). We get \(x=-14+15 = 1\).

Answer:

1