Question

the axis of symmetry for the function $f(x) = -2x^2 + 4x + 1$ is the line $x = 1$. where is the vertex of the function located?\
$\circ$ $(0, 1)$\
$\circ$ $(1, 3)$\
$\circ$ $(1, 7)$\
$\circ$ $(2, 1)$

Explanation:

Step1: Substitute x=1 into f(x)

$f(1) = -2(1)^2 + 4(1) + 1$

Step2: Calculate the value

$f(1) = -2 + 4 + 1 = 3$

Step3: Identify vertex coordinates

Vertex is $(1, f(1)) = (1, 3)$

Answer:

B. (1, 3)