Question

a bag contains six yellow tickets numbered one to six and four green tickets numbered one to four. if you randomly pick a ticket, return it to the bag, then pick another ticket, what is the probability that both tickets were green?

Explanation:

Step1: Calculate total tickets

Total tickets = 6 yellow + 4 green = 10

Step2: Find single green probability

Probability of green ticket: $\frac{\text{Number of green tickets}}{\text{Total tickets}} = \frac{4}{10} = \frac{2}{5}$

Step3: Calculate combined probability

Since tickets are replaced, events are independent. Multiply single probabilities: $\frac{2}{5} \times \frac{2}{5}$

Answer:

$\frac{4}{25}$ or 0.16