Question

× not balanced try again hide why 1 n₂ + 3 o₂ → 5 n₂o

Explanation:

Step1: Count initial N atoms

Reactant side: $1 \times 2 = 2$; Product side: $5 \times 2 = 10$

Step2: Count initial O atoms

Reactant side: $3 \times 2 = 6$; Product side: $5 \times 1 = 5$

Step3: Balance N atoms first

Set coefficient of $\text{N}_2$ as $a$, $\text{N}_2\text{O}$ as $b$. $2a = 2b \implies a = b$. Let $b=2$, so $a=2$. Now N: $2\times2=4$, $2\times2=4$.

Step4: Balance O atoms

Reactant O: $2c = 2\times1=2 \implies c=1$. Now check:
Reactants: $2\text{N}_2$ (4 N) + $1\text{O}_2$ (2 O)
Products: $2\text{N}_2\text{O}$ (4 N, 2 O)

Answer:

The balanced chemical equation is $\boldsymbol{2N_2 + O_2
ightarrow 2N_2O}$