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Question
balancing chemical equations - worksheet #1
balance the following chemical equations:
- __al (s) + hcl (aq) alcl3 (aq) + __h2 (g)
- __k (s) + h2o (l) koh (aq) + __h2 (g)
- __mg (s) + n2 (g) __mg3n2 (s)
- __nano3 (s) nano2 (s) + __o2 (g)
- __ca(oh)2 (s) + h3po4 (aq) ca3(po4)2 (s) + __h2o (l)
- __c3h8 (g) + o2 (g) co2 (g) + __h2o (g)
- __nh3 (g) + o2 (g) no (g) + __h2 (g)
- __n2 (g) + h2 (g) __nh3 (g)
- __na2co3 (s) + hcl (aq) nacl (aq) + co2 (g) + __h2o (l)
- __c3h5oh (l) + o2 (g) co2 (g) + __h2o (g)
- __nh3 (g) + cuo (s) n2 (g) + cu (s) + __h2o (g)
- __cu (s) + agno3 (aq) ag (s) + __cu(no3)2 (aq)
- __c12h22o11 (s) + o2 (g) co2 (g) + __h2o (g)
- __feo (s) + o2 (g) __fe2o3 (s)
- __cs2 (l) + nh3 (g) h2s (g) + __nh4scn (s)
- __naoh (aq) + hno3 (aq) nano3 (aq) + __h2o (l)
Step1: Balance equation 1
Balance the number of atoms on both sides. For the reaction $\text{Al}(s)+\text{HCl}(aq)
ightarrow\text{AlCl}_3(aq)+\text{H}_2(g)$, we get $2\text{Al}(s) + 6\text{HCl}(aq)=2\text{AlCl}_3(aq)+3\text{H}_2(g)$
Step2: Balance equation 2
For $\text{K}(s)+\text{H}_2\text{O}(l)
ightarrow\text{KOH}(aq)+\text{H}_2(g)$, we have $2\text{K}(s)+2\text{H}_2\text{O}(l)=2\text{KOH}(aq)+\text{H}_2(g)$
Step3: Balance equation 3
For $\text{Mg}(s)+\text{N}_2(g)
ightarrow\text{Mg}_3\text{N}_2(s)$, it is $3\text{Mg}(s)+\text{N}_2(g)=\text{Mg}_3\text{N}_2(s)$
Step4: Balance equation 4
For $\text{NaNO}_3(s)
ightarrow\text{NaNO}_2(s)+\text{O}_2(g)$, we get $2\text{NaNO}_3(s)=2\text{NaNO}_2(s)+\text{O}_2(g)$
Step5: Balance equation 5
For $\text{Ca(OH)}_2(s)+\text{H}_3\text{PO}_4(aq)
ightarrow\text{Ca}_3(\text{PO}_4)_2(s)+\text{H}_2\text{O}(l)$, we have $3\text{Ca(OH)}_2(s)+2\text{H}_3\text{PO}_4(aq)=\text{Ca}_3(\text{PO}_4)_2(s)+6\text{H}_2\text{O}(l)$
Step6: Balance equation 6
For $\text{C}_3\text{H}_8(g)+\text{O}_2(g)
ightarrow\text{CO}_2(g)+\text{H}_2\text{O}(g)$, we get $\text{C}_3\text{H}_8(g)+5\text{O}_2(g)=3\text{CO}_2(g)+4\text{H}_2\text{O}(g)$
Step7: Balance equation 7
For $\text{NH}_3(g)+\text{O}_2(g)
ightarrow\text{NO}(g)+\text{H}_2(g)$, we have $4\text{NH}_3(g)+5\text{O}_2(g)=4\text{NO}(g)+6\text{H}_2(g)$
Step8: Balance equation 8
For $\text{N}_2(g)+\text{H}_2(g)
ightarrow\text{NH}_3(g)$, we get $\text{N}_2(g)+3\text{H}_2(g)=2\text{NH}_3(g)$
Step9: Balance equation 9
For $\text{Na}_2\text{CO}_3(s)+\text{HCl}(aq)
ightarrow\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$, we have $\text{Na}_2\text{CO}_3(s)+2\text{HCl}(aq)=2\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$
Step10: Balance equation 10
For $\text{C}_3\text{H}_5\text{OH}(l)+\text{O}_2(g)
ightarrow\text{CO}_2(g)+\text{H}_2\text{O}(g)$, we get $\text{C}_3\text{H}_5\text{OH}(l)+9\text{O}_2(g)=6\text{CO}_2(g)+8\text{H}_2\text{O}(g)$
Step11: Balance equation 11
For $\text{NH}_3(g)+\text{CuO}(s)
ightarrow\text{N}_2(g)+\text{Cu}(s)+\text{H}_2\text{O}(g)$, we have $2\text{NH}_3(g)+3\text{CuO}(s)=\text{N}_2(g)+3\text{Cu}(s)+3\text{H}_2\text{O}(g)$
Step12: Balance equation 12
For $\text{Cu}(s)+\text{AgNO}_3(aq)
ightarrow\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$, we get $\text{Cu}(s)+2\text{AgNO}_3(aq)=2\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$
Step13: Balance equation 13
For $\text{C}_{12}\text{H}_{22}\text{O}_{11}(s)+\text{O}_2(g)
ightarrow\text{CO}_2(g)+\text{H}_2\text{O}(g)$, we get $\text{C}_{12}\text{H}_{22}\text{O}_{11}(s)+12\text{O}_2(g)=12\text{CO}_2(g)+11\text{H}_2\text{O}(g)$
Step14: Balance equation 14
For $\text{FeO}(s)+\text{O}_2(g)
ightarrow\text{Fe}_2\text{O}_3(s)$, we get $4\text{FeO}(s)+\text{O}_2(g)=2\text{Fe}_2\text{O}_3(s)$
Step15: Balance equation 15
For $\text{CS}_2(l)+\text{NH}_3(g)
ightarrow\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$, we get $\text{CS}_2(l)+2\text{NH}_3(g)=\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$
Step16: Balance equation 16
For $\text{NaOH}(aq)+\text{HNO}_3(aq)
ightarrow\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$, we get $\text{NaOH}(aq)+\text{HNO}_3(aq)=\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$
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- $2\text{Al}(s) + 6\text{HCl}(aq)=2\text{AlCl}_3(aq)+3\text{H}_2(g)$
- $2\text{K}(s)+2\text{H}_2\text{O}(l)=2\text{KOH}(aq)+\text{H}_2(g)$
- $3\text{Mg}(s)+\text{N}_2(g)=\text{Mg}_3\text{N}_2(s)$
- $2\text{NaNO}_3(s)=2\text{NaNO}_2(s)+\text{O}_2(g)$
- $3\text{Ca(OH)}_2(s)+2\text{H}_3\text{PO}_4(aq)=\text{Ca}_3(\text{PO}_4)_2(s)+6\text{H}_2\text{O}(l)$
- $\text{C}_3\text{H}_8(g)+5\text{O}_2(g)=3\text{CO}_2(g)+4\text{H}_2\text{O}(g)$
- $4\text{NH}_3(g)+5\text{O}_2(g)=4\text{NO}(g)+6\text{H}_2(g)$
- $\text{N}_2(g)+3\text{H}_2(g)=2\text{NH}_3(g)$
- $\text{Na}_2\text{CO}_3(s)+2\text{HCl}(aq)=2\text{NaCl}(aq)+\text{CO}_2(g)+\text{H}_2\text{O}(l)$
- $\text{C}_3\text{H}_5\text{OH}(l)+9\text{O}_2(g)=6\text{CO}_2(g)+8\text{H}_2\text{O}(g)$
- $2\text{NH}_3(g)+3\text{CuO}(s)=\text{N}_2(g)+3\text{Cu}(s)+3\text{H}_2\text{O}(g)$
- $\text{Cu}(s)+2\text{AgNO}_3(aq)=2\text{Ag}(s)+\text{Cu(NO}_3)_2(aq)$
- $\text{C}_{12}\text{H}_{22}\text{O}_{11}(s)+12\text{O}_2(g)=12\text{CO}_2(g)+11\text{H}_2\text{O}(g)$
- $4\text{FeO}(s)+\text{O}_2(g)=2\text{Fe}_2\text{O}_3(s)$
- $\text{CS}_2(l)+2\text{NH}_3(g)=\text{H}_2\text{S}(g)+\text{NH}_4\text{SCN}(s)$
- $\text{NaOH}(aq)+\text{HNO}_3(aq)=\text{NaNO}_3(aq)+\text{H}_2\text{O}(l)$