Question

a ball is drawn randomly from a jar that contains 2 red balls, 4 white balls, and 7 yellow balls. find the probability of the given event. write your answers as reduced fractions or whole numbers. (a) $p(\text{a red ball is drawn}) = $ (b) $p(\text{a white ball is drawn}) = $ (c) $p(\text{a yellow ball is drawn}) = $ (d) $p(\text{a green ball is drawn}) = $

Explanation:

Step1: Calculate total number of balls

$2 + 4+7=13$

Step2: Calculate probability of red - ball

The number of red balls is 2. So $P(\text{A red ball is drawn})=\frac{2}{13}$

Step3: Calculate probability of white - ball

The number of white balls is 4. So $P(\text{A white ball is drawn})=\frac{4}{13}$

Step4: Calculate probability of yellow - ball

The number of yellow balls is 7. So $P(\text{A yellow ball is drawn})=\frac{7}{13}$

Step5: Calculate probability of green - ball

There are 0 green balls. So $P(\text{A green ball is drawn}) = 0$

Answer:

(a) $\frac{2}{13}$
(b) $\frac{4}{13}$
(c) $\frac{7}{13}$
(d) $0$