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is being under the age of 12 independent of visiting the inventions exh…

Question

is being under the age of 12 independent of visiting the inventions exhibit at this museum? justify the conclusion.
no, because 0.074≠(0.368)(0.321)
yes, because 0.074=(0.368)(0.321)
no, because 0.118≠(0.368)(0.321)
yes, because 0.118=(0.368)(0.321)

under 1212 - 25over 25
modern art5817
inventions142819
aerospace1679

Explanation:

Step1: Calculate total number of visitors

First, sum all the values in the table. $12 + 20+35 + 17+8 + 5+19+28+14+9+7+16=180$.

Step2: Calculate probability of being under 12

The number of visitors under 12 is $35 + 5+14+16 = 70$. The probability $P(\text{under }12)=\frac{70}{180}\approx0.389$.

Step3: Calculate probability of visiting inventions exhibit

The number of visitors to inventions exhibit is $19 + 28+14 = 61$. The probability $P(\text{inventions})=\frac{61}{180}\approx0.339$.

Step4: Calculate probability of being under 12 and visiting inventions exhibit

The number of visitors who are under 12 and visit inventions exhibit is 14. The probability $P(\text{under }12\text{ and inventions})=\frac{14}{180}\approx0.078$.

Step5: Check for independence

If two events $A$ (being under 12) and $B$ (visiting inventions exhibit) are independent, then $P(A\cap B)=P(A)\times P(B)$. $P(A)\times P(B)=\frac{70}{180}\times\frac{61}{180}=\frac{4270}{32400}\approx0.132
eq0.078 = P(A\cap B)$.

Answer:

No, because $0.078
eq(0.389)(0.339)$ (approximate values used for the non - equality check based on the calculated probabilities).