Question

1. a billboard has the given dimensions.

Explanation:

Assuming the problem is to find the area of the billboard (since it's a rectangle with length \(7^2\) ft and width \(4^2\) ft), we can solve it as follows:

Step1: Calculate \(7^2\) and \(4^2\)

First, we find the values of \(7^2\) and \(4^2\).
\(7^2 = 7\times7 = 49\)
\(4^2 = 4\times4 = 16\)

Step2: Calculate the area of the rectangle

The area \(A\) of a rectangle is given by the formula \(A=\text{length}\times\text{width}\). Here, the length is \(7^2 = 49\) ft and the width is \(4^2 = 16\) ft. So we multiply these two values:
\(A = 49\times16\)
\(49\times16=(50 - 1)\times16 = 50\times16-1\times16=800 - 16 = 784\) square feet.

Alternatively, using the properties of exponents, we can also calculate the area as \((7\times4)^2\) (since \(a^m\times b^m=(ab)^m\)).
First, \(7\times4 = 28\), then \(28^2=28\times28 = 784\) square feet.

Answer:

The area of the billboard is \(\boldsymbol{784}\) square feet.