Question

bridget and karen are reading the same book for english class. bridget has already read 25 pages, and she continues to read at a rate of 15 pages per day. karen is just starting the book, and she reads at a rate of 20 pages per day. how many days will it take before karen has read the same number of pages as bridget? how many pages will each person have read? it will take \boxed{} days before each person has read \boxed{} pages. submit

Explanation:

Step1: Define variables and equations

Let \( d \) be the number of days. Bridget's total pages read: \( 25 + 15d \). Karen's total pages read: \( 20d \). Set them equal: \( 25 + 15d = 20d \).

Step2: Solve for \( d \)

Subtract \( 15d \) from both sides: \( 25 = 5d \). Divide by 5: \( d = 5 \).

Step3: Find total pages

Substitute \( d = 5 \) into Karen's equation: \( 20 \times 5 = 100 \). Or Bridget's: \( 25 + 15 \times 5 = 25 + 75 = 100 \).

Answer:

It will take \( \boldsymbol{5} \) days before each person has read \( \boldsymbol{100} \) pages.