Question

calculate the amount (mol) of solute delivered to the dilute solution. 2.00 ml of 0.0400 m solution was added. mol

Explanation:

Step1: Recall molarity formula

$n = M\times V$, where $n$ is the amount of solute in moles, $M$ is molarity and $V$ is volume in liters.

Step2: Convert volume to liters

$V=2.00\ mL = 2.00\times10^{- 3}\ L$

Step3: Substitute values into formula

$n = 0.0400\ M\times2.00\times10^{-3}\ L$
$n=8.00\times 10^{-5}\ mol$

Answer:

$8.00\times 10^{-5}$