Question

calculate the distance between the points a=(0, 4) and m=(6, -1) in the coordinate plane. round your answer to the nearest hundredth. distance:

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1 = 0,y_1 = 4,x_2=6,y_2=- 1$.

Step2: Substitute values

$d=\sqrt{(6 - 0)^2+(-1 - 4)^2}=\sqrt{6^2+(-5)^2}=\sqrt{36 + 25}=\sqrt{61}$.

Step3: Calculate and round

$\sqrt{61}\approx 7.81$.

Answer:

$7.81$