Question

calculate the first and second velocities of the car with one washer attached to the pulley, using the formulas v1 = 0.25 m / t1, and v2 = 0.25 m / (t2 - t1) where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. record these velocities, rounded to two decimal places, in table e. what is the first velocity of the car with one washer at the 0.25 meter mark? m/s what is the second velocity of the car with one washer at the 0.50 meter mark? m/s

Explanation:

Step1: Determine first - velocity formula

The formula for the first velocity is $v_1 = 0.25\ m/t_1$. You need to know the value of $t_1$ (the average time the car took to reach the 0.25 - meter mark) to calculate $v_1$.

Step2: Determine second - velocity formula

The formula for the second velocity is $v_2=0.25\ m/(t_2 - t_1)$. You need to know the values of $t_1$ (average time to 0.25 - meter mark) and $t_2$ (average time to 0.50 - meter mark) to calculate $v_2$.

Since the values of $t_1$ and $t_2$ are not given in the problem, we cannot calculate the actual numerical values. But if we assume $t_1 = a$ seconds and $t_2=b$ seconds:

Step3: Calculate first velocity

$v_1=\frac{0.25}{a}$ (in m/s).

Step4: Calculate second velocity

$v_2=\frac{0.25}{b - a}$ (in m/s).

Answer:

Since $t_1$ and $t_2$ are not given, we cannot provide numerical answers. The first velocity formula is $v_1=\frac{0.25}{t_1}$ and the second velocity formula is $v_2=\frac{0.25}{t_2 - t_1}$ (where $t_1$ and $t_2$ are the average times to reach 0.25 - meter and 0.50 - meter marks respectively).