Question

calculate $\delta$h (kj/mol) for ca(oh)$_2$ in the dissociation process.
$q_{rxn}$ = $-$1677 joules \\ 0.100 mol ca(oh)$_2$
$\delta$h = $\frac{-1677\\ j}{0.100\\ mol}$ $\times$ $\frac{1\\ kj}{1000\\ j}$
$\delta$ h = ? kj/mol
enter either a + or - sign and the magnitude.
be careful with your units in this step!

Explanation:

Step1: Perform the division of -1677 J by 0.100 mol

$\frac{-1677\space J}{0.100\space mol} = -16770\space \frac{J}{mol}$

Step2: Convert joules to kilojoules by multiplying with the conversion factor

$-16770\space \frac{J}{mol} \times \frac{1\space kJ}{1000\space J} = -16.77\space \frac{kJ}{mol}$

Answer:

-16.77