calculate the missing information and then draw a bohr diagram and lewis structure for each element. li atomic # = 3 mass # = 7 # of p = ___ # of n = ___ # of e = ___ ne atomic # = 10 mass # = 20 # of p = ___ # of n = ___ # of e = ___ mg atomic # = 12 mass # = 24 # of p = ___ # of n = ___ # of e = ___ cl atomic # = 17 mass # = 35 # of p = ___ # of n = ___ # of e = ___ he atomic # = 2 mass # = 4 # of p = ___ # of n = ___ # of e = ___ si atomic # = 14 mass # = 28 # of p = ___ # of n = ___ # of e = ___

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Accepted Answer

# Explanation:
## Step1: Recall atomic - related definitions
The atomic number ($Z$) is equal to the number of protons ($P$) and for a neutral atom, the number of electrons ($E$). The mass number ($A$) is the sum of protons and neutrons ($N$), so $N=A - P$.
## Step2: For Li (Atomic # = 3, Mass # = 7)
The number of protons $P = 3$ (since atomic number = number of protons). The number of neutrons $N=A - P=7 - 3 = 4$. The number of electrons $E = 3$ (for a neutral atom).
## Step3: For Ne (Atomic # = 10, Mass # = 20)
The number of protons $P = 10$. The number of neutrons $N=A - P=20 - 10 = 10$. The number of electrons $E = 10$.
## Step4: For Mg (Atomic # = 12, Mass # = 24)
The number of protons $P = 12$. The number of neutrons $N=A - P=24 - 12 = 12$. The number of electrons $E = 12$.
## Step5: For Cl (Atomic # = 17, Mass # = 35)
The number of protons $P = 17$. The number of neutrons $N=A - P=35 - 17 = 18$. The number of electrons $E = 17$.
## Step6: For He (Atomic # = 2, Mass # = 4)
The number of protons $P = 2$. The number of neutrons $N=A - P=4 - 2 = 2$. The number of electrons $E = 2$.
## Step7: For Si (Atomic # = 14, Mass # = 28)
The number of protons $P = 14$. The number of neutrons $N=A - P=28 - 14 = 14$. The number of electrons $E = 14$.

# Answer:
| Element | # of P | # of N | # of E |
| ---- | ---- | ---- | ---- |
| Li | 3 | 4 | 3 |
| Ne | 10 | 10 | 10 |
| Mg | 12 | 12 | 12 |
| Cl | 17 | 18 | 17 |
| He | 2 | 2 | 2 |
| Si | 14 | 14 | 14 |

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Question

Explanation:

Step1: Recall atomic - related definitions

Step2: For Li (Atomic # = 3, Mass # = 7)

Step3: For Ne (Atomic # = 10, Mass # = 20)

Step4: For Mg (Atomic # = 12, Mass # = 24)

Step5: For Cl (Atomic # = 17, Mass # = 35)

Step6: For He (Atomic # = 2, Mass # = 4)

Step7: For Si (Atomic # = 14, Mass # = 28)

Answer: