Question

calculate the probability of drawing a blue, followed by a red marble. no replacement. what is the probability of drawing a red marble? $\frac{1}{10} \times \frac{2}{?}=\frac{2}{}=\frac{}{}$

Explanation:

Step1: Determine the total number of marbles after first - draw

There are originally 10 marbles. After drawing a blue marble (1 blue marble out of 10), there are 9 marbles left for the second - draw.

Step2: Calculate the probability of the combined event

The probability of drawing a blue marble first is $\frac{1}{10}$ (1 blue marble out of 10). The probability of drawing a red marble second (after drawing a blue marble without replacement) is $\frac{2}{9}$ (2 red marbles out of the remaining 9 marbles). The probability of the combined event (blue then red) is $\frac{1}{10}\times\frac{2}{9}=\frac{2}{90}=\frac{1}{45}$.

Answer:

$\frac{1}{45}$