Question

1. calculate the relative atomic mass for titanium using the following information

$_{22}^{46}ti = 8.25\\%$
$_{22}^{47}ti = 7.44\\%$
$_{22}^{48}ti = 73.72\\%$
$_{22}^{49}ti = 5.41\\%$
$_{22}^{50}ti = 5.18\\%$

1. calculate the relative atomic mass for germanium

$_{32}^{70}ge = 20.84\\%$
$_{32}^{72}ge = 27.54\\%$
$_{32}^{73}ge = 7.73\\%$
$_{32}^{74}ge = 36.28\\%$
$_{32}^{76}ge = 7.61\\%$

Explanation:

Step1: Recall relative - atomic - mass formula

The relative atomic mass ($A_r$) of an element is calculated as $A_r=\sum_{i} (m_i\times p_i)$, where $m_i$ is the mass number of the isotope and $p_i$ is the percentage abundance of the isotope (expressed as a decimal). For Titanium:
The mass numbers of the isotopes are 46, 47, 48, 49, 50 respectively.

Step2: Convert percentages to decimals

$8.25\% = 0.0825$, $7.44\%=0.0744$, $73.72\% = 0.7372$, $5.41\%=0.0541$, $5.18\% = 0.0518$.

Step3: Calculate relative atomic mass of Titanium

$A_r=(46\times0.0825)+(47\times0.0744)+(48\times0.7372)+(49\times0.0541)+(50\times0.0518)$
$A_r = 3.795+3.4968 + 35.3856+2.6509+2.59$
$A_r=47.9183\approx47.92$

Answer:

47.92