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Question
calculate the value of the fraction \\(\dfrac{13^{\frac{3}{7}}}{13^{\frac{5}{7}}}\\)
Step1: Recall the exponent rule for division
When dividing two numbers with the same base, we subtract the exponents: $a^m \div a^n = a^{m - n}$. Here, we can rewrite the given expression as a division of two exponents with base 13: $13^{\frac{3}{7}} \div 13^{\frac{5}{7}}$.
Step2: Apply the exponent division rule
Using the rule $a^m \div a^n = a^{m - n}$, where $a = 13$, $m=\frac{3}{7}$, and $n = \frac{5}{7}$, we get $13^{\frac{3}{7}-\frac{5}{7}}$.
Step3: Simplify the exponent
Calculate the exponent: $\frac{3}{7}-\frac{5}{7}=\frac{3 - 5}{7}=\frac{-2}{7}$. So the expression becomes $13^{-\frac{2}{7}}$.
Step4: Rewrite the negative exponent
A negative exponent means the reciprocal of the positive exponent: $a^{-n}=\frac{1}{a^n}$. So $13^{-\frac{2}{7}}=\frac{1}{13^{\frac{2}{7}}}$.
Step5: Rewrite the fractional exponent as a root
Recall that $a^{\frac{m}{n}}=\sqrt[n]{a^m}$. So $13^{\frac{2}{7}}=\sqrt[7]{13^2}=\sqrt[7]{169}$. Thus, the expression is $\frac{1}{\sqrt[7]{169}}$ or we can also write it as $169^{-\frac{1}{7}}$.
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$13^{-\frac{2}{7}}$ (or $\frac{1}{\sqrt[7]{169}}$ or $169^{-\frac{1}{7}}$)