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Question
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what is the measure of ∠j to the nearest degree?
45°
55°
70°
83°
Step1: Apply Law of Sines
$\frac{\sin(\angle J)}{GH} = \frac{\sin(\angle G)}{JH}$
Step2: Substitute known values
$\frac{\sin(\angle J)}{5} = \frac{\sin(80^\circ)}{7}$
Step3: Isolate $\sin(\angle J)$
$\sin(\angle J) = \frac{5 \times \sin(80^\circ)}{7}$
Step4: Calculate the value
$\sin(\angle J) \approx \frac{5 \times 0.9848}{7} \approx 0.7034$
Step5: Find $\angle J$ via arcsine
$\angle J \approx \arcsin(0.7034) \approx 45^\circ$
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45°