QUESTION IMAGE
Question
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which function is shown on the graph?
$f(x) = -\frac{1}{2}sin x$
$f(x) = \frac{1}{2}sin x$
$f(x) = \frac{1}{2}cos x$
$f(x) = -\frac{1}{2}cos x$
Step1: Check x=0 value
At $x=0$, the graph has a positive y-value.
- For $f(x)=-\frac{1}{2}\sin x$: $f(0)=-\frac{1}{2}\sin0=0$ (does not match)
- For $f(x)=\frac{1}{2}\sin x$: $f(0)=\frac{1}{2}\sin0=0$ (does not match)
- For $f(x)=\frac{1}{2}\cos x$: $f(0)=\frac{1}{2}\cos0=\frac{1}{2}$ (positive, matches)
- For $f(x)=-\frac{1}{2}\cos x$: $f(0)=-\frac{1}{2}\cos0=-\frac{1}{2}$ (negative, does not match)
Step2: Verify midline/shape
The graph has the shape of a cosine curve (starts at a peak, oscillates) with amplitude $\frac{1}{2}$, consistent with $f(x)=\frac{1}{2}\cos x$.
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$f(x)=\frac{1}{2}\cos x$