Question

1. a candy store grab bag contains 10 pieces of sour candy, 12 pieces of chocolate candy, and 6 pieces of sweet candy. if you select 1 piece of candy, replace it, and then select another piece, what is the probability that the first piece of candy taken out is a sour candy and the second piece of candy taken out is not a sour candy? 23% 92% 29% 100%

Explanation:

Step1: Calculate total candies

$10 + 12 + 6 = 28$

Step2: Probability first is sour

$\frac{10}{28} \approx 0.3571$

Step3: Probability second not sour

$\frac{28 - 10}{28} = \frac{18}{28} \approx 0.6429$

Step4: Multiply the two probabilities

$0.3571 \times 0.6429 \approx 0.2286$

Step5: Convert to percentage

$0.2286 \times 100\% \approx 23\%$

Answer:

23%