Question

ccss 6th grade math review 10b 1. 0.16 • 0.09 = 2. \\(\sqrt7{39.2}\\) 3. \\(\sqrt0.5{27.6}\\) 4. convert each fraction to a decimal. \\(\frac{2}{3}\\) = \\(\frac{1}{8}\\) =

Explanation:

Problem 1: \( 0.16 \cdot 0.09 = \)

Step 1: Multiply the numbers as if they were whole numbers.

\( 16 \times 9 = 144 \)

Step 2: Count the total number of decimal places.

\( 0.16 \) has 2 decimal places, \( 0.09 \) has 2 decimal places. Total decimal places: \( 2 + 2 = 4 \)

Step 3: Place the decimal in the product.

\( 144 \) with 4 decimal places is \( 0.0144 \)

Step 1: Divide 39 by 7.

\( 7 \times 5 = 35 \), \( 39 - 35 = 4 \)

Step 2: Bring down the 2 (from 39.2) to make 42.

\( 42 \div 7 = 6 \)

Step 3: The decimal point in the quotient aligns with the dividend's decimal.

So, \( 39.2 \div 7 = 5.6 \)

Step 1: Multiply dividend and divisor by 10 to eliminate the decimal in the divisor.

\( 27.6 \times 10 = 276 \), \( 0.5 \times 10 = 5 \)

Step 2: Divide 276 by 5.

\( 5 \times 55 = 275 \), \( 276 - 275 = 1 \). Add a decimal and a zero: \( 10 \div 5 = 2 \)

Step 3: Combine the results.

\( 276 \div 5 = 55.2 \)

Answer:

\( 0.0144 \)

Problem 2: \(

$$\begin{array}{r}7\enclose{longdiv}{39.2}\end{array}$$

\)