Question

a census was conducted that determined the land area and populations of towns in a certain region. the frequency table displays some of the results. rounded to the nearest hundredth, what values complete the conditional relative frequency table? a = b =

Explanation:

Step1: Recall the property of conditional - relative frequency table

In a conditional - relative frequency table, the sum of the conditional - relative frequencies in each row is 1.

Step2: Calculate the value of \(a\)

For the row with area \(< 20\) sq. mi., \(a=0.2 + 0.73=0.93\).

Step3: Calculate the value of \(b\)

For the row with area \(> 20\) sq. mi., \(b = 0.8+0.28 = 1.08\) (but this is incorrect. There was a rounding - error in the given values. Since the sum of relative frequencies in a row must be 1, we should calculate based on the original data. The correct way: For the row with area \(> 20\) sq. mi., the sum of relative frequencies of the two sub - categories should be 1. So \(b = 1\)). For the row with area \(<20\) sq. mi., \(a = 1\) as well.

Answer:

\(a = 1\)
\(b = 1\)