Question

ch. 1.2 - segment addition postulate
find the lengths of the following.
find be. (b to the first e), so find 3x - 28
b 3x - 28 e 3x - 30 f x e
33
be =

Explanation:

Step1: Apply segment - addition postulate

$(3x - 28)+(3x - 30)+x=33$

Step2: Combine like - terms

$3x+3x + x-28 - 30=33$
$7x-58 = 33$

Step3: Solve for x

$7x=33 + 58$
$7x=91$
$x = 13$

Step4: Find the length of BE

Substitute $x = 13$ into the expression for BE.
$BE=3x-28$
$BE=3\times13-28$
$BE = 39-28$
$BE = 11$

Answer:

$11$