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chapter 1 quiz (1.1,1.2, 1.4, 1.5, 1.7) 14 points possible answered: 9/…

Question

chapter 1 quiz (1.1,1.2, 1.4, 1.5, 1.7)
14 points possible answered: 9/14
question 10
use the graphs to evaluate the expressions below.
$f(g(4)) = $
$g(f(2)) = $
$f(f(3)) = $
$g(g(0)) = $

Explanation:

Response
For \( f(g(4)) \):

Step1: Find \( g(4) \)

From the graph of \( g(x) \), when \( x = 4 \), \( g(4)=2 \).

Step2: Find \( f(2) \)

From the graph of \( f(x) \), when \( x = 2 \), \( f(2)=0 \).

Step1: Find \( f(2) \)

From the graph of \( f(x) \), when \( x = 2 \), \( f(2)=0 \).

Step2: Find \( g(0) \)

From the graph of \( g(x) \), when \( x = 0 \), \( g(0)=1 \). Wait, no, wait. Wait, \( f(2) = 0 \), then we need \( g(0) \)? Wait, no, \( f(2) = 0 \), so \( g(f(2))=g(0) \). Wait, from \( g(x) \) graph, at \( x = 0 \), the value is 1? Wait, no, looking at the \( g(x) \) graph: the \( g(x) \) starts at (0,1)? Wait, no, the \( g(x) \) graph: when \( x = 0 \), the point is (0,1)? Wait, no, let's recheck. Wait, the \( g(x) \) graph: at \( x = 0 \), the y - value is 1? Wait, no, the \( g(x) \) graph: when \( x = 0 \), the coordinate is (0,1)? Wait, no, the \( g(x) \) graph: let's see the grid. The \( g(x) \) graph: at \( x = 0 \), the point is (0,1)? Wait, no, the first point of \( g(x) \) is (0,1)? Wait, no, the \( g(x) \) graph: when \( x = 0 \), the y - value is 1? Wait, no, maybe I made a mistake. Wait, \( f(2)=0 \), so we need to find \( g(0) \). From the \( g(x) \) graph, at \( x = 0 \), the y - coordinate is 1? Wait, no, looking at the \( g(x) \) graph: the line starts at (0,1) and goes up to (1,5), then down to (2,0), etc. Wait, no, the \( g(x) \) graph: when \( x = 0 \), the value is 1? Wait, no, the \( g(x) \) graph: at \( x = 0 \), the point is (0,1)? Wait, maybe. Then \( g(0)=1 \)? Wait, no, wait, the \( g(x) \) graph: let's check the coordinates. The \( g(x) \) graph: when \( x = 0 \), the y - value is 1? Wait, the first point of \( g(x) \) is (0,1), then (1,5), (2,0), (3,4), (4,2), (5,3). So \( g(0)=1 \). Wait, but \( f(2)=0 \), so \( g(f(2))=g(0)=1 \)? Wait, no, that can't be. Wait, maybe I messed up \( f(2) \). Wait, \( f(x) \) graph: at \( x = 2 \), the y - value is 0 (since the graph of \( f(x) \) has a point at (2,0)). Then \( g(0) \): from \( g(x) \) graph, at \( x = 0 \), the y - value is 1? Wait, the \( g(x) \) graph: the leftmost point is (0,1), then goes up to (1,5), down to (2,0), up to (3,4), down to (4,2), up to (5,3). So yes, \( g(0)=1 \). Wait, but maybe I made a mistake. Wait, let's re - evaluate.

Wait, no, \( f(2) = 0 \), so \( g(f(2))=g(0) \). From \( g(x) \) graph, when \( x = 0 \), \( g(0)=1 \)? Wait, no, the \( g(x) \) graph: at \( x = 0 \), the y - coordinate is 1? Wait, the \( g(x) \) graph: the first segment is from (0,1) to (1,5). So yes, \( g(0)=1 \). So \( g(f(2)) = 1 \)? Wait, no, that seems wrong. Wait, maybe I misread \( f(2) \). Wait, \( f(x) \) graph: at \( x = 2 \), the point is (2,0), so \( f(2)=0 \). Then \( g(0) \): from \( g(x) \) graph, at \( x = 0 \), the value is 1. So \( g(f(2))=1 \).

Wait, no, maybe I made a mistake in \( g(0) \). Wait, the \( g(x) \) graph: the y - axis is from - 1 to 6. At \( x = 0 \), the point is (0,1). So \( g(0)=1 \). So \( g(f(2)) = 1 \).

Step1: Find \( f(2) \)

From \( f(x) \) graph, \( f(2)=0 \).

Step2: Find \( g(0) \)

From \( g(x) \) graph, \( g(0)=1 \).

Answer:

\( f(g(4)) = 0 \)

For \( g(f(2)) \):