Question

chapter 3: 3.3 two basic rules of probability homework score: 4/14 answered: 2/8 question 3 a survey of athletes at a high school is conducted, and the following facts are discovered: 49% of the athletes are football players, 31% are basketball players, and 20% of the athletes play both football and basketball. an athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player? probability = % (please enter your answer as a percent)

Explanation:

Step1: Recall the formula

Use the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$, where $A$ is the event of being a football - player and $B$ is the event of being a basketball - player.

Step2: Identify the probabilities

We are given that $P(A) = 49\%=0.49$, $P(B)=31\% = 0.31$, and $P(A\cap B)=20\%=0.2$.

Step3: Calculate the probability

Substitute the values into the formula: $P(A\cup B)=0.49 + 0.31-0.2$.
$P(A\cup B)=0.6$.

Answer:

60%