Question

check here for instructional material to complete this problem. evaluate $sigma=sqrt{np(1 - p)}$ for $n = 36$, $p = 0.5$. $sigma=square$ (simplify your answer. type an integer or decimal rounded to one decimal place as needed.)

Explanation:

Step1: Substitute values into formula

Substitute $n = 36$ and $p=0.5$ into $\sigma=\sqrt{np(1 - p)}$, we get $\sigma=\sqrt{36\times0.5\times(1 - 0.5)}$.

Step2: Calculate the value inside the square - root

First, calculate $1-0.5 = 0.5$. Then $36\times0.5\times0.5=36\times0.25 = 9$.

Step3: Calculate the square - root

$\sigma=\sqrt{9}=3$.

Answer:

$3$